If a solution contains 9 mg of salt per 1000 mL, how many mg of salt are needed for 250 mL?

Master the NLN PAX Mathematics 1 Exam with our comprehensive study guide and quizzes. Test your knowledge with multiple choice questions tailored for the PAX Math exam, featuring detailed explanations and tips to enhance your preparation and increase your chances of success.

Multiple Choice

If a solution contains 9 mg of salt per 1000 mL, how many mg of salt are needed for 250 mL?

Explanation:
This question tests proportionality and how to scale a given quantity to a different volume. If you have 9 mg of salt in 1000 mL, the amount per mL is 9/1000 = 0.009 mg/mL. For 250 mL, multiply: 0.009 × 250 = 2.25 mg. Another quick way is to note that 250 mL is a quarter of 1000 mL, so the amount is a quarter of 9 mg, which is 9 ÷ 4 = 2.25 mg. So 2.25 mg of salt are needed.

This question tests proportionality and how to scale a given quantity to a different volume. If you have 9 mg of salt in 1000 mL, the amount per mL is 9/1000 = 0.009 mg/mL. For 250 mL, multiply: 0.009 × 250 = 2.25 mg. Another quick way is to note that 250 mL is a quarter of 1000 mL, so the amount is a quarter of 9 mg, which is 9 ÷ 4 = 2.25 mg. So 2.25 mg of salt are needed.

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